Hey all,

I was wondering if you could help me?

How do you intergrate the function (1-sin^2x)?

I'm really lost with the whole intergration of cos^2x and sin^2x

Thanks

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- Nov 3rd 2007, 01:06 AMTrevKIntergration of trig function (1-sin^2x)
Hey all,

I was wondering if you could help me?

How do you intergrate the function (1-sin^2x)?

I'm really lost with the whole intergration of cos^2x and sin^2x

Thanks - Nov 3rd 2007, 02:19 AMred_dog
$\displaystyle \displaystyle\int(1-\sin^2x)dx=\int\cos^2xdx=\int\frac{1+\cos 2x}{2}dx$

Now, continue from here.