# Intergration of trig function (1-sin^2x)

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• November 3rd 2007, 01:06 AM
TrevK
Intergration of trig function (1-sin^2x)
Hey all,
I was wondering if you could help me?
How do you intergrate the function (1-sin^2x)?
I'm really lost with the whole intergration of cos^2x and sin^2x
Thanks
• November 3rd 2007, 02:19 AM
red_dog
$\displaystyle\int(1-\sin^2x)dx=\int\cos^2xdx=\int\frac{1+\cos 2x}{2}dx$
Now, continue from here.