The derivatives are:

And:

So:

Setting f'(x) = 0, we get:

Now we can't simply divide by (x-2), or we will be missing out on a solution, so instead we factor out:

Then, after substituting these values back into the original equation, we get the stationary points as:

2,0),\left(\frac{2}{3},\frac{256}{81}\right)\rbrac e}" alt="\lbrace{(x,y)2,0),\left(\frac{2}{3},\frac{256}{81}\right)\rbrac e}" />