Hello, togo!
You are using for two different quantities.
We have: .
Let
Substitute: .
Back-substitute: .
Question: Integrate 28-1-16
(int) 0.8((3 + 2 ln(u))^3) du/u
My attempt:
u = (3 + 2 ln u)
du = 2(1/u) = 2/u
My guess at this is to divide the whole integral by 2 now since it has been multiplied by 2 in the derivative.
resulting in this:
0.4[3 + 2 ln u]/4
I used a Ti-89 and got a very weird answer. Any clues as to what went wrong? thanks.