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Find the derivative of the fn f(x)=(2x-3)^4(x^2+x+1)^5

I've attempted this, and a number of other problems from the Stewart calculus book, 2.5 #17.

I think I Have the right answer so far, but I've no idea how to factor something so complex. I've looked over the answer, and an example in the book, but can't work out what they are doing. I'd really appreciate some help, but given that I have no idea what I need to be doing here, I might need more than just a small tip.

Attachment 28268

Re: Find the derivative of the fn f(x)=(2x-3)^4(x^2+x+1)^5

Yes, you are correct so far, now what you want to do is factor.

Re: Find the derivative of the fn f(x)=(2x-3)^4(x^2+x+1)^5

thats the problem, I have no idea how.

I am aware that its probably got something to do with the (2x-3) and (x^2+x+1)

Re: Find the derivative of the fn f(x)=(2x-3)^4(x^2+x+1)^5

How would you factor:

$\displaystyle au^4v^4+bu^3v^5$ ?

Re: Find the derivative of the fn f(x)=(2x-3)^4(x^2+x+1)^5

Quote:

Originally Posted by

**limitofx** I've attempted this, and a number of other problems from the Stewart calculus book, 2.5 #17.

I think I Have the right answer so far, but I've no idea how to factor something so complex. I've looked over the answer, and an example in the book, but can't work out what they are doing. I'd really appreciate some help, but given that I have no idea what I need to be doing here, I might need more than just a small tip.

Attachment 28268

You might want to check this website.

Math Forum - Ask Dr. Math

It explains how to expand large functions with power. Hope it helps.