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Math Help - Natural Logarithms

  1. #1
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    Natural Logarithms

    I was wondering if I could get any help on this, I'm quite not sure what I'm doing wrong
    Natural Logarithms-logarithms.png
    Any help would be much appreciated

    Thanks!
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  2. #2
    MHF Contributor MarkFL's Avatar
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    Re: Natural Logarithms

    You want to use:

    \log_a(b)-\log_a(c)=\log_a\left(\frac{b}{c} \right)

    not:

    \log_a(b)-\log_a(c)=\frac{\log_a(b)}{c}

    The latter is not an identity.
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  3. #3
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    Re: Natural Logarithms

    Ahh, simple!

    Thanks for that.
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