Re: sketching curve graph

f(x) is increasing where f'(x) > 0.

f(x) is decreasing where f'(x) < 0.

Local maxima and minima occur where f'(x) = 0. If it's a maximum then f''(x) < 0 at that point, and if it's a minimum then f''(x) > 0 at that point.

To sketch the graph, find the critical points, the x and y intercepts and then you have enough info to sketch...

Re: sketching curve graph

yes i know that, but im stuck after getting the first derivative. i know i have to get the critical points after that but, how do i make that derivative equal 0 and get a value for it? it dosnt factor...

Re: sketching curve graph

To find out where 3x^2+4x-1 is zero, since it won't factor easily, use the quadratic equation....

- Hollywood

Re: sketching curve graph

Quote:

Originally Posted by

**hollywood** To find out where 3x^2+4x-1 is zero, since it won't factor easily, use the quadratic equation....

- Hollywood

Use the Quadratic FORMULA :)

Re: sketching curve graph

using the quadratic formula (just the cas calc) i got x=2 or x=-1 or x=1

does that sound about right?

Re: sketching curve graph

ok im doing something wrong because im just not getting it. can someone PLEASE just start me off?? get me past this particular step..thanks

Re: sketching curve graph

You have the correct first derivative...and you should know that a quadratic has only two roots, I don't know how you obtained three. Don't use the CAS, plug into the quadratic formula, and what do you find...show your work so we can see what you did wrong if you don't get the correct roots.

Re: sketching curve graph

https://www.dropbox.com/s/7vw527ndhy...2000.22.56.jpg

how's this??? why does this looks so complicated??

where do i go from here. find at which inteervals the function is increasing/decreasing?? how do u do that with square roots? (hate them, btw)

Re: sketching curve graph

You are correct...we don't always get rational roots. Now these two roots give you 3 open intervals on the real number line, and since the roots are not repeated, we know the sign of the derivative will alternate across the intervals, so I would choose the test point of zero in the middle interval. What is the sign of $\displaystyle f'(0)$? Once you have this, then you know the sign of the derivative is the opposite of this on the other two intervals. And this will tell you where the original function is increasing/decreasing. What do you find?

Re: sketching curve graph

im lost......but is this close to what im supposed to do??

https://www.dropbox.com/s/ns1bp0mkom...2000.53.26.jpg

Re: sketching curve graph

You have correctly used the roots of the derivative to divide the number line, but the sign associated with the leftmost interval should be positive, for the reason I cited above. If you wish to test all 3 intervals, I would use integers...-2 for the leftmost interval, 0 for the middle and 1 for the rightmost. Get decimal approximations for the roots of the derivative, and you will see why these work.

Re: sketching curve graph

is that always the case? since f(0) is (-), then the other two intervals will always be positive?

and just to be sure, to get the signs, im plugging in numbers into the derivative or the original equation? i plugged (-1) and (1) on the left and right intervals into the derivative. but i think youre supposed to use the original, no ?

Re: sketching curve graph

It is only the case when the roots are of odd multiplicity, here your two roots are both of multiplicity 1, so we know the sign will alternate.

You want to check the sign of the derivative, since a positive derivative means the original function is increasing, while a negative derivative means it is decreasing. -1 is in the same interval as 0, that's why I suggest using -2 as a test point for the leftmost interval.

Re: sketching curve graph

okay...gotcha.

now the next step is finding the inflection point, right? how does this look?

is it an inflection point? function is increasing on both sides. (Thinking)

https://www.dropbox.com/s/h7hviziib6...2001.24.56.jpg