Hi, I´m having trouble solving this limit, without using the L´Hospital. I tried dividing it into a sum and using Newtons binomial, but i arrived at which i am not able to solve. The answer should be e.
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Hey HK47. Hint: Separate the fraction by using (2x+3)/(2x+1) = (2x + 1 + 2)/(2x+1) = 1 + 2/(2x+1) and look at the formula for e in terms of (1 + 1/n)^n.
Thanks, expanded the binomial and discovered, that the constant doesnt contribute into the result. Problem solved.
Try using the code: \lim_{x\to c}f(x) for your limits.
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