Hi, I´m having trouble solving this limit, without using the L´Hospital.

I tried dividing it into a sum and using Newtons binomial, but i arrived at

which i am not able to solve. The answer should be e.

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- May 2nd 2013, 02:21 AMHK47Limit problem.
Hi, I´m having trouble solving this limit, without using the L´Hospital.

I tried dividing it into a sum and using Newtons binomial, but i arrived at

which i am not able to solve. The answer should be e. - May 2nd 2013, 03:13 AMchiroRe: Limit problem.
Hey HK47.

Hint: Separate the fraction by using (2x+3)/(2x+1) = (2x + 1 + 2)/(2x+1) = 1 + 2/(2x+1) and look at the formula for e in terms of (1 + 1/n)^n. - May 4th 2013, 02:57 AMHK47Re: Limit problem.
Thanks, expanded the binomial and discovered, that the constant doesnt contribute into the result.

Problem solved. - May 4th 2013, 03:13 AMMarkFLRe: Limit problem.
Try using the code:

\lim_{x\to c}f(x)

for your limits. :D