Hi,
Could I get some help with solving this. It's probably really simple but I'm not too sure how to approach it
______
'Find the equation of the tangent to the curve y=x√2x² + 7 at x=3'
Any help would be much appreciated.
Many thanks,
Moob
Hi,
Could I get some help with solving this. It's probably really simple but I'm not too sure how to approach it
______
'Find the equation of the tangent to the curve y=x√2x² + 7 at x=3'
Any help would be much appreciated.
Many thanks,
Moob
I can't read this. Is your function $\displaystyle \displaystyle \begin{align*} y = x\,\sqrt{2}\,x^2 + 7 \end{align*}$ or $\displaystyle \displaystyle \begin{align*} y = x\,\sqrt{2x^2} + 7 \end{align*}$ or even $\displaystyle \displaystyle \begin{align*} y = x\,\sqrt{2x^2 + 7} \end{align*}$?
Well the tangent line, being a line, will have equation $\displaystyle \displaystyle \begin{align*} y = mx + c \end{align*}$, so you need its gradient and its y-intercept. How will you find the gradient? How will you find the y intercept?
I've tried subbing 3 for x, this left me with
Attachment 28224
I am most likely way off in the method I'm using.
Thanks once again.