Hey icelated.
Confirming you answers with Octave, we get:
>> >> A = [1, -1, 0; 4, -3, -1; 2, -1, -1]
A =
1 -1 0
4 -3 -1
2 -1 -1
>> rref(A)
ans =
1 0 -1
0 1 -1
0 0 0
This confirms your results as correct.
I have a problem where i don't have the solution to since i like to practice odd problems.
I am not sure if i have done this correctly.
Determine whether the lines
L1:
L2:
are parallel, intersecting, or skew. If they intersect find the point of intersection.
Attempt: Take L2 and re-write it using t=s to make it simpler
L2:
Make them parametric:
(1)
(2)
(3)
Solve (1) for t
Solve(2) for s
so, and
Solve (3) by subbing in t and s
Therefore, two lines intersect. Not parallel.
To find the point of intersection:
Solve L1 for
L1:
point: (0, -1, 2)
Is this correct? Or did i do this completely wrong?
Thank you
Hey icelated.
Confirming you answers with Octave, we get:
>> >> A = [1, -1, 0; 4, -3, -1; 2, -1, -1]
A =
1 -1 0
4 -3 -1
2 -1 -1
>> rref(A)
ans =
1 0 -1
0 1 -1
0 0 0
This confirms your results as correct.