1. ## Continuity

Any help with this question would be very appreciated

2. ## Re: Continuity

In order for the function to be continuous at a point, it needs to be defined at that point (which it is at x = 1) and needs to approach the same value from the left as from the right.

So that means in order to be continuous at x = 1, then \displaystyle \begin{align*} \ln{(1)} = 1.7^1 - C \end{align*} (do you see why?) Solve for C.

3. ## Re: Continuity

I had done that method, I just didn't get more than 1 value for c, and the question says values, so I was confused. I mainly need help with part b, to show that g is differentiable at x=1.

4. ## Re: Continuity

I am checking by finding the derivatives of both by first principles, and checking if the values that those equations produce at x=1 are the same, I am not too certain whether I am doing the right thing there :S. And I am mainly stuck on the derivative of ln(x) by first principles. I can get to: lim h->0 ln(1+h/x)/h