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Math Help - Help with a Limit Problem

  1. #1
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    Exclamation Help with a Limit Problem

    I don't understand how to go about doing this problem:

    The limit of numerator (1/3 + deltaX)^2 - (1/9) divided by denominator deltaX as deltaX approaches 0.

    Any help will be much appreciated!
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  2. #2
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    Use this \left( {\frac{1}{3} + \Delta x} \right)^2  - \frac{1}{9} = \frac{{2\Delta x}}{3} + \left( {\Delta x} \right)^2 .
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  3. #3
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    Quote Originally Posted by Plato View Post
    Use this \left( {\frac{1}{3} + \Delta x} \right)^2  - \frac{1}{9} = \frac{{2\Delta x}}{3} + \left( {\Delta x} \right)^2 .
    What happens to the 1/9?
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  4. #4
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    Quote Originally Posted by blurain View Post
    What happens to the 1/9?
    It goes away because you have (1/9) - (1/9) = 0.
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