I don't understand how to go about doing this problem: The limit of numerator (1/3 + deltaX)^2 - (1/9) divided by denominator deltaX as deltaX approaches 0. Any help will be much appreciated!
Follow Math Help Forum on Facebook and Google+
Use this $\displaystyle \left( {\frac{1}{3} + \Delta x} \right)^2 - \frac{1}{9} = \frac{{2\Delta x}}{3} + \left( {\Delta x} \right)^2 $.
Originally Posted by Plato Use this $\displaystyle \left( {\frac{1}{3} + \Delta x} \right)^2 - \frac{1}{9} = \frac{{2\Delta x}}{3} + \left( {\Delta x} \right)^2 $. What happens to the 1/9?
Originally Posted by blurain What happens to the 1/9? It goes away because you have (1/9) - (1/9) = 0.
View Tag Cloud