Now, note that is the semi unit circle of radius 2. Thus, the area is
Note, use direct subsitution to evaluate
Then and
Then = which equals zero.
Therefore,
Finishing the last chapter of Calculus 1, so go easy on me you guys :|
I know this is like the easiest and most obvious thing. I just can't figure it out though; I need help.
I don't know why the answer is 6π.
Evaluate ∫ from -2 to 2 of (x + 3)(4 - x^2)1/2 dx by writing it as a sum of two integrals and interpreting one of those integrals in terms of an area.
Why? And how is this done?