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Math Help - Find integral of polar function h(r,theta) = rcos(theta) over a circle

  1. #1
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    Find integral of polar function h(r,theta) = rcos(theta) over a circle

    Hello,

    I am studying for my math final and our prof gave us a review but without any solutions or hints. I don't really understand this problem so if anyone could help me out here I would appreciate it.

    Question: Find the integral of the polar function h(r, theta) = r cos(theta) , r >= 0, over
    the circle r = 2a cos(theta) .

    Again I would appreciate the help.
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  2. #2
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    Re: Find integral of polar function h(r,theta) = rcos(theta) over a circle

    Hey lytwynk.

    Are you integrating a double integral over the region that is bounded by a circle with radius 2*a with centre (0,0) or are you integrating a line integral with the boundary equal to that same circle?
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  3. #3
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    Re: Find integral of polar function h(r,theta) = rcos(theta) over a circle

    To be honest I am not sure. The question was written word for word. Just any insight into what I should do would be helpful.
    Thanks
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  4. #4
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    Re: Find integral of polar function h(r,theta) = rcos(theta) over a circle

    I'm going to assume its over a 2D region defined by a circle since r >= 0.

    Hint: With regards to your limits the integral will have r going from 0 to 2a and theta going from 0 to 2*pi.
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  5. #5
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    Re: Find integral of polar function h(r,theta) = rcos(theta) over a circle

    OK, I think I got it now. Thanks for the help.
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