. this is how i solve this, but i know it's not true.. why? so,
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I find the approach absolutely correct.
I don't see where you went wrong myself, and your result agrees with mine.
but look here: lim sqrt(x^2+x)-x - Wolfram|Alpha
Yes, and as the limit is 1/2.
Originally Posted by MarkFL Yes, and as the limit is 1/2. and what about the limit as , which it's the case we're dealing with?
I missed the negative sign...in that case I would rewrite the limit as:
didn't understand you.. what in this case?
In the case of I substituted x with -x...
Originally Posted by orir . this is how i solve this, but i know it's not true.. why? so, Because at the begining of the last line you should have had: rather than: If you want to try going down that route. .
Last edited by zzephod; April 26th 2013 at 02:54 AM.
ok.. so i still don't get how it should be solved
Originally Posted by orir i still don't get how it should be solved Please note the problem is In effect it is . To see that let then we have , which is large.
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