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Math Help - Integration

  1. #1
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    Integration

    I = (x+1)*(1-x)^(1/3) dx
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  2. #2
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    Re: Integration

    Quote Originally Posted by jdesak View Post
    I = (x+1)*(1-x)^(1/3) dx

    Write it as \int {{u^{\frac{1}{3}}}} \left( {2 - u} \right)\left( { - du} \right) and expand.
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  3. #3
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    Re: Integration

    In other words, because it is that "1/3 power" that is the hard part, use the substitution u= 1- x (or equivaently u= x- 1).
    Thanks from MarkFL
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