I need to decide whether the following statement is true or not:

let f be a complex function, f(z)=f(x+iy)=u(x,y)+iv(x,y).if u and v satisfy the Cauchy-Riemann equations in a neighborhood of z_0 then f is differentiable at z_0.

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- Nov 1st 2007, 09:04 PMLiav TeichnerDerivatives and the Cauchy-Riemann equations
I need to decide whether the following statement is true or not:

let f be a complex function, f(z)=f(x+iy)=u(x,y)+iv(x,y).if u and v satisfy the Cauchy-Riemann equations in a neighborhood of z_0 then f is differentiable at z_0. - Nov 1st 2007, 09:10 PMThePerfectHacker
False.

This is Mine 75:):)th Post!!! - Nov 1st 2007, 09:17 PMJhevon
- Nov 1st 2007, 09:25 PMLiav TeichnerI don't think the example is correct:
"if u and v satisfy the Cauchy-Riemann equations in a neighborhood of z_0" - It means there's an open circle (disk) around z0 where the Cauchy-Rieamann equations are satisfied. In your example there is no such circle (neighborhood). Every circle around (0,0) in your example contain positive real numbers where it is easy to show the Cauchy-Riemann equations aren't satisfied.