Thread: Continuity

f(x)=
(Square root -x) x<0
3-x 0<(or equal to) x<3
(x-3)^3 x>3


Its all Part of the function.
Where is it continous?

Originally Posted by meg24209

f(x)=
(Square root -x) x<0
3-x 0<(or equal to) x<3
(x-3)^3 x>3


Its all Part of the function.
Where is it continous?

The only places where it has a chance of being discontinuities are: 0, 3.
Now to check this take the limit right the right and left at these point and see if they agree.