f(x)= (Square root -x) x<0 3-x 0<(or equal to) x<3 (x-3)^3 x>3 Its all Part of the function. Where is it continous?
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Originally Posted by meg24209 f(x)= (Square root -x) x<0 3-x 0<(or equal to) x<3 (x-3)^3 x>3 Its all Part of the function. Where is it continous? The only places where it has a chance of being discontinuities are: 0, 3. Now to check this take the limit right the right and left at these point and see if they agree.
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