1. Continuity

f(x)=
(Square root -x) x<0
3-x 0<(or equal to) x<3
(x-3)^3 x>3

Its all Part of the function.
Where is it continous?

2. Originally Posted by meg24209
f(x)=
(Square root -x) x<0
3-x 0<(or equal to) x<3
(x-3)^3 x>3

Its all Part of the function.
Where is it continous?
The only places where it has a chance of being discontinuities are: 0, 3.
Now to check this take the limit right the right and left at these point and see if they agree.