Could someone please help me solve this integral: I = squareroot(1-x^2) dx
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Start by substituting x = sin(w), so that dx = cos(w) dw. You'll end up having to integrate , and to do that you can use the half angle formula: . Try it, and post back with what you get.
You may want to check this page which has detailed instructions(and demonstration) on how to integrate as a definite integral. For indefinite integral the procedure is same. definite integrals
To make it easier I re-edited the post. We have to evaluate:
Here it is again:
Let's think of and in the above question as two sides of a right triangle.
Hope it helps.
Last edited by x3bnm; April 23rd 2013 at 01:28 PM.
Note that either x= sin(w), as suggested by ebaines, or [itex]x= sin(\theta)[/itex], as suggested by X3bnm, will work in exactly the same way.
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