f(x) = 1/2 e^x and g(x) = sech(x). I have already worked out that there are no x intercepts for either graph and that f(x) intercepts the y axis at 1/2 and g(x) intercepts it at 1.
when i tried to find the intercept between the two curves I got the x value = (log 3) / 2, making the y value = 0 which i know is incorrect. i believe my x value is right i just dont know what to do to get the right y value.
the area needed to be calculated is between the graphs between 0 and the intersection point, since i think its log 3 / 2, i worked it out to be (3+3 sqrt(3)+pi)/6. just wondering if that is correct