when you derive h/500 i know that h would turn into 1 but since 500 is a constant would that just be 0? please someone explain???
Follow Math Help Forum on Facebook and Google+
do i not derive the constant when differentiating implicitly?
Last edited by asilvester635; Apr 20th 2013 at 10:50 AM.
I think you assume that h is a function of t, so $\displaystyle \frac{d}{dt} \frac{h(t)}{500} = \frac{d}{dt} \frac{1}{500} h(t) = \frac{1}{500} \frac{dh(t)}{dt}$. - Hollywood
View Tag Cloud