Question: Find the point on the curve y=e^2x+1 where the tangent is parallel to the line y=2ex.
Please help. Thanks.
You set y' = 2e^(2x+1) = 2e and solve for x. The slope of the other curve, y=2ex, is 2e. So x=0, right?
All three of us were confused about what the function was; you really should have cleared that up in addition to asking for clarification.