# Thread: Surface integral - hemisphere

1. ## Surface integral - hemisphere

Below is a question I have for an assignment. It is saying that number 2 is wrong. Cannot for the life of me work out why. Please help

Let A be the area of the hemisphere of radius 8 which given by:

x2+y2+z2=64 where 0z4
1. Indicate the correct parameterisation of the surface:
 (x,y,z)=S(u,v)=64(cosusinv,sinusinv,cosv); where 0≤u≤2π,π3≤v≤π2 (x,y,z)=S(u,v)=8(cosusinv,sinusinv,cosv); where 0≤u≤2π,π3≤v≤π2 (x,y,z)=S(u,v)=8(cosusinv,sinusinv,cosv); where 0≤u≤2π,0≤v≤π3 (x,y,z)=S(u,v)=8(cosusinv,sinusinv,cosv); where 0≤v≤2π,π3≤u≤π2
2. Find the normal to the surface N(u,v)=Su×Sv=
64( -cos u sin^2 v, -sin u sin^2 v, -sin v cosv)