W|A agrees with you:
d/dx((x^2-6x+1)/(x^4-1)) where x=2 - Wolfram|Alpha
W|A agrees with you:
d/dx((x^2-6x+1)/(x^4-1)) where x=2 - Wolfram|Alpha
Hey grillage.
For this kind of thing I use a computer package to eliminate the human error aspect. Using Wolfram Alpha, we get:
d/dx((x^2 - 6x + 1)/((x^2+1)*(x^2-1))) - Wolfram|Alpha
Plugging in x = 2 gives us
dy/dx|x = 2 = 194/225 which is in agreement with your value.