Thread: integral calculas???

r(t)=dr/dt=0.05e^.02t (200-t)

r(0)=1000

using integral calculas i need to show that r(t)=2.5e^.02t (250-t)+375

How is this found???

Your question is a little unreadable.

But I could see that you need to solve a differential equation with initial condition.

If the rate of growth of the number of wasps at time t days is given by -

r(t)=dr/dt=0.05e^.02t (200-t), r(0)=1000

show that the number of reproductive wasp r(t) at time t equals -

2.5e^.02t (250-t)+375

Originally Posted by softdrink_jr

If the rate of growth of the number of wasps at time t days is given by -

r(t)=dr/dt=0.05e^.02t (200-t), r(0)=1000

show that the number of reproductive wasp r(t) at time t equals -

2.5e^.02t (250-t)+375

is this what you want?


where

and show that


but why is that ?