# work - calculus

• Oct 31st 2007, 11:59 PM
kittycat
work - calculus
given the force vector field F = <y,a> .
Find the work in moving an object through the vector field along the closed curve C formed by the arc of the ellipse x=acost , y=bsint, lying in the first quadrant, the x-axis, and the y-axis.

• Nov 1st 2007, 04:48 AM
kalagota
Quote:

Originally Posted by kittycat
given the force vector field F = <y,a> .
Find the work in moving an object through the vector field along the closed curve C formed by the arc of the ellipse x=acost , y=bsint, lying in the first quadrant, the x-axis, and the y-axis.

have you checked the previous post about work?
so,
$r(t) = x(t)i + y(t)j = (a \cos t)i + (b \sin t)j$
where t is from 0 to $\, \frac{\pi}{2}$
and
$F(x,y) = yi + aj$

note that
$W = \int_C F \cdot dr = \int_C \cdot $
$\, = \int_0^{\frac{\pi}{2}} y(t)dx(t) + a dy(t)$

can you continue?
• Nov 1st 2007, 05:45 AM
CaptainBlack
Quote:

Originally Posted by kittycat
given the force vector field F = <y,a> .
Find the work in moving an object through the vector field along the closed curve C formed by the arc of the ellipse x=acost , y=bsint, lying in the first quadrant, the x-axis, and the y-axis.

Quote:

Originally Posted by kalagota
have you checked the previous post about work?
so,
$r(t) = x(t)i + y(t)j = (a \cos t)i + (b \sin t)j$
where t is from 0 to $\, \frac{\pi}{2}$
and
$F(x,y) = yi + aj$

Assuming kalagota is right and $F(x,y) = yi + aj$ is what is meant by F = <y,a> what field of study did you get this notation from. I'm sure that I'm not the only person at least partialy mystified by this notation

RonL
• Nov 1st 2007, 06:45 AM
kalagota
Quote:

Originally Posted by CaptainBlack
Assuming kalagota is right and $F(x,y) = yi + aj$ is what is meant by F = <y,a> what field of study did you get this notation from. I'm sure that I'm not the only person at least partialy mystified by this notation

RonL

we also that notation for vector fields, i.e. if we have a Field vector
$F(x,y)$
then it is equivalent to saying that
$F(x,y) = $
• Nov 1st 2007, 08:08 AM
CaptainBlack
Quote:

Originally Posted by kalagota
we also that notation for vector fields, i.e. if we have a Field vector
$F(x,y)$
then it is equivalent to saying that
$F(x,y) = $

Yes, but in this context who is the "we" you refer to?

That is what area of study uses this notation (I ask because it is not used
in any thing I have studies in this way).

RonL
• Nov 1st 2007, 07:07 PM
Jhevon
Quote:

Originally Posted by CaptainBlack
Yes, but in this context who is the "we" you refer to?

That is what area of study uses this notation (I ask because it is not used
in any thing I have studies in this way).

RonL

i've seen that notation before. it is from vector calculus, and you see it even in calc 3. in general we can use $\left< x_1, x_2, ..., x_n \right>$ to represent a vector with $n$ components. if the components are functions, as opposed to just numbers, we obtain a vector field, that is, a function that assigns an nth dimensional vector to each point
• Nov 1st 2007, 08:26 PM
kalagota
Quote:

Originally Posted by CaptainBlack
Yes, but in this context who is the "we" you refer to?

That is what area of study uses this notation (I ask because it is not used
in any thing I have studies in this way).

RonL

"we" as in all students of math/physics in our university..
we used it in our calc 3 also..