the area of shaded region. You have to subtract the two equations and take the integral from -3/4 to 3/2 right?
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No, the integral would be from -3/4 to 0 because that's the x coordinates of where they intersect.
Thank you!!
The area in this case should be considered between the curve and y axis. It would not be appropriate as well as possible to consider the area between the curve and the x axis. Please have a look at the attached solution.
Thanks a ton! I solved it and got integral 0 to 3/2 of -2y^2 +3y =9/8 after plugging in the limits etc.
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