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Math Help - Help with factorial limit

  1. #1
    Junior Member Shadow236's Avatar
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    Help with factorial limit

    Okays so, I have the limit as n-> infinity: (20n!)/((n+1)!)

    My first thought is that you would divided all terms by n, basically making the limit = 20!/1!, which is just 20!... but I don't think that this is correct. What do you guys think?

    Thanks.
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  2. #2
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    Re: Help with factorial limit

    Quote Originally Posted by Shadow236 View Post
    Okays so, I have the limit as n-> infinity: (20n!)/((n+1)!)

    Well, if it as you posted it \frac{20\cdot n!}{(n+1)!}=\frac{20}{n+1}.

    But is it meant to be \frac{(20n)!}{(n+1)!}~?
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  3. #3
    Junior Member Shadow236's Avatar
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    Re: Help with factorial limit

    It should be the first way you have it. If that's so, how do you get to 20/(n + 1)?
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    Re: Help with factorial limit

    (20 x n(n-1)...1)/1x2x3x4x...n(n+1) = 20/(n+1) after simplification its easy.
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    Re: Help with factorial limit

    Quote Originally Posted by Shadow236 View Post
    It should be the first way you have it. If that's so, how do you get to 20/(n + 1)?
    (n+1)!=(n+1)(n!)
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