it would be wise to find b before a. setting the derivative = 0 will give the horizontal tangent
At time t, the position of a particle moving on a curve is given by
x=e^(2t)-e^(-2t) , y=3e^(2t)+e^(-2t)
(a) Find the value of t at which the curve has a horizontal tangent.
t =
(b) Find dy/dx in terms of t.
dy/dx =
(c) Find .
can somone help me do this one...plzzzzz...thanks....
mathation