Evaluate the surface integral ∫ ∫ (x+y) ds where D is the part of the plane x+2y+3z=6 above the triangle in the xy-plane with vertices at (0,0,0), (1,0,0), and (1,1,0).

I get 1/2 aqrt(14/9) as final answer. Is it correct?

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- Apr 8th 2013, 06:06 PMapatiteSurface Integral
Evaluate the surface integral ∫ ∫ (x+y) ds where D is the part of the plane x+2y+3z=6 above the triangle in the xy-plane with vertices at (0,0,0), (1,0,0), and (1,1,0).

I get 1/2 aqrt(14/9) as final answer. Is it correct? - Apr 9th 2013, 06:28 AMHallsofIvyRe: Surface Integral
Yes, that's what I get.