Find the point on the line 4x+4y+3=0 which is closet to P (1, 2)?
So I re wrote my line as y=-x-(3/4)
Then i take d^2=(x-1)^2+(-x-(3/4)-2)^2=2x^2+(7x/2)+(137/16)
Once I take the dirivative i get 4x+(7/2) soove for x i get -(7/8) and then y = 1/8
But its wrong. What did i do wrong?