Originally Posted by

**MINOANMAN** M670

The slope intercept form of the equation of the given line L is : y = -1x-(3/4)

the closest point on the line L from the point P(1,2) is the point that the perpendicular line to the line L , passing from the point P, intecects the line L.

the equation of the line that passes from the point P and is perpendicular to L is y = x+1

to find the coordinates of the point of intercection of these two lines solve the system of the two simultaneous equations

y = -1x-3/4

y=x+1

the answer is x=-7/8 and y= 1/8 therefore the point is Q(-7/8 , 1/8)

Pls revise the equation of the line in the plane .