# Evaluate the limits (trigonometric) #2

$\lim_{x\to\0}\frac{\6x + 6sin(x)}{4x + 4cos(x)}$ , when evalated gives me $\frac{0 + 0}{0 + 1}$ which equals to $\0/1$ and it's 0 ;
there is really nothing to do with it and the limit is $\0$?