I have such a limit $\displaystyle \lim_{x \to{\pi/2}^+}{7cos(x)}/{1-sin (x)}$ which is of type 0/0

by applying l'Hospital rule I get

$\displaystyle \lim_{x \to{\pi/2}^+}{-7sin(x)}/{-cos(x)} = $,

$\displaystyle 7 *\lim_{x \to{\pi/2}^+}{tan(x)} = $

$\displaystyle 7 * -\infty $,

$\displaystyle - \infty $, and it makes sense for me by visualizing the graph,

what do you think?