Find all values of x for which the function is differentiable.
$\displaystyle y= \frac {x^3 - 8}{x^2 -4x-5}$
Easy way out is graphing.
Is there an algebraic way of figuring this out?
It looks to me that x=2 does not work, for the nominator equals 0.
x=5 appears to give on discontinuity, as the denominator is 0.
Anything I missed?
Thanks.