I have to differentiate this function: f(x)=x + 2/3x^2-1 if i can also get the forumla for differentiation that will also be a big help Thanks in advance
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Originally Posted by excelsion f(x)=x + 2/3x^2-1 Please, use the appropriate brackets when posting. $\displaystyle f(x)=\frac{x+2}{3x^2-1}\,?$ Then rewrite the function as $\displaystyle (x+2)(3x^2-1)^{-1}.$ Now to take its derivative, use the product rule and remember the chain rule.
sorry about that lemme try..... is it 9x^2+12x-1 actually should it be 6x+1? first time forgot the ^-1 from putting bottom up top
Huh? May I ask if you write the full question please?
it just says: Differentiate: f(x)= (x+2)/(3x^2-1)
Okay. Anyway, I didn't understand the post #3 Well then, follow the given instructions on post #2.
i did that and got 6x+1 is that correct?
I'm afraid it is not. You can use this useful tool to check your work.
that suggest i use quotient rule but im not dividing two fuctions im just trying to find the derivative of that one fucntion
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