Find the equation of the tangent line to the graph of y= 5e^x(x^2+x-1)^(-x) at the point where x=1
is that meant to read $\displaystyle y= 5e^x (x^2+x-1)^{-x}$ in any case get what $\displaystyle y$ would be by substituting in $\displaystyle x=1$ then get $\displaystyle dy/dx$ of the original $\displaystyle y= 5e^x (x^2+x-1)^(-x)$ and then use the equation of a line formula [TEX]y-y_1=m(x-x_1) where $\displaystyle m=dy/dx$. Hope this helps.