Results 1 to 3 of 3

Math Help - Equation of Tangent Line

  1. #1
    Newbie
    Joined
    Mar 2013
    From
    US
    Posts
    6

    Equation of Tangent Line

    Find the equation of the tangent line to the graph of y= 5e^x(x^2+x-1)^(-x) at the point where x=1
    Last edited by hellokitty999; March 27th 2013 at 09:36 AM.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Newbie
    Joined
    Mar 2013
    From
    dublin
    Posts
    19
    Thanks
    2

    Re: Equation of Tangent Line

    is that meant to read y= 5e^x (x^2+x-1)^{-x} in any case get what y would be by substituting in x=1 then get dy/dx of the original y= 5e^x (x^2+x-1)^(-x) and then use the equation of a line formula [TEX]y-y_1=m(x-x_1) where m=dy/dx. Hope this helps.
    Follow Math Help Forum on Facebook and Google+

  3. #3
    MHF Contributor

    Joined
    Apr 2005
    Posts
    15,790
    Thanks
    1531

    Re: Equation of Tangent Line

    I presume you can do the derivative of 5e^x. To differentiate u= (x^2+ x- 1)^{-x} take the logarithm, ln(u)= -x ln(x^2+ x- 1) and differentiate both sides with respect to x.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 6
    Last Post: January 12th 2011, 02:38 PM
  2. Equation of the Tangent Line
    Posted in the Calculus Forum
    Replies: 1
    Last Post: August 10th 2010, 07:46 PM
  3. equation for tangent line
    Posted in the Calculus Forum
    Replies: 2
    Last Post: January 5th 2009, 09:51 AM
  4. equation of tangent line
    Posted in the Calculus Forum
    Replies: 2
    Last Post: October 13th 2008, 08:15 AM
  5. Equation of a tangent line
    Posted in the Trigonometry Forum
    Replies: 1
    Last Post: December 16th 2005, 12:03 PM

Search Tags


/mathhelpforum @mathhelpforum