# Equation of Tangent Line

is that meant to read $y= 5e^x (x^2+x-1)^{-x}$ in any case get what $y$ would be by substituting in $x=1$ then get $dy/dx$ of the original $y= 5e^x (x^2+x-1)^(-x)$ and then use the equation of a line formula [TEX]y-y_1=m(x-x_1) where $m=dy/dx$. Hope this helps.