# Math Help - Working out the level of homogeneity

1. ## Working out the level of homogeneity

I know that q= 120L1 1/2 K - (L3/√K) has homogenous degree of 2 1/2 but I'm unsure how that has been worked out. I think its the square root thats throwing me, could someone show me how its 2 1/2?

2. ## Re: Working out the level of homogeneity

In this case, homogeneous means that the sum of the exponents of L and K for the first term is the same as the sum of the exponents of L and K for the second term.

For the first term, L has exponent $1\,\frac{1}{2}$ and K has exponent 1, so the sum is $2\,\frac{1}{2}$. For the second term, L has exponent 3 and K has exponent $-\frac{1}{2}$ (since $K^{-\frac{1}{2}}=\frac{1}{\sqrt{K}}$), so the sum is again $2\,\frac{1}{2}$.

- Hollywood

3. ## Re: Working out the level of homogeneity

Thank you, for some reason I was adding those terms together.