I know that q= 120L^{1 1/2} K - (L^{3}/√K) has homogenous degree of 2 1/2 but I'm unsure how that has been worked out. I think its the square root thats throwing me, could someone show me how its 2 1/2?
Thanks in advance.
I know that q= 120L^{1 1/2} K - (L^{3}/√K) has homogenous degree of 2 1/2 but I'm unsure how that has been worked out. I think its the square root thats throwing me, could someone show me how its 2 1/2?
Thanks in advance.
In this case, homogeneous means that the sum of the exponents of L and K for the first term is the same as the sum of the exponents of L and K for the second term.
For the first term, L has exponent and K has exponent 1, so the sum is . For the second term, L has exponent 3 and K has exponent (since ), so the sum is again .
- Hollywood