Use the Maclaurin series (e^x) = sum from k=0 to infinity of ((x^k)/(k!)) to find the Maclaurin series for ((e^x)-1)/(x) x can't equal zero.
It would be wise for future posts if you learned some simple latex to make your questions legible, and therefore helpers may be more inclined to help you. We are given the following Maclaurin series for $\displaystyle e^x$
$\displaystyle e^x = \sum_{k=0}^{\infty} \frac{x^k}{k!}$
HINT: Replace $\displaystyle e^x$ with the above sum in the expression $\displaystyle \frac{e^{x}-1}{x}$ and see what cancels out (expand the sum if necessary). What you will be left with is the Maclaurin series for $\displaystyle \frac{e^{x}-1}{x}$