Nth term in a geometric series
Attachment 27637So for this I have calculated what I believe to be the correct few terms of Q and P Q0=75, Q1=84, Q2=94.08. Always increasing by 12% of what the previous function was. I can't understand why my formula didn't work. I also tried using Qn=Q0*Rn-1 but that provided an answer for n=0that was smaller than 75.
*Edit, I understand that I cant use n-1 because we're starting from n=0 and not n=1 so shouldn't it just be Qn=Q0*Rn?
Re: Nth term in a geometric series
If I understand the question correctly, then
, in other words, what remains in the system on the previous day plus the new dose of 75mg per day.
EDIT:// this appears right in terms of a recursive equation, now all you would need to do is simplify to closed form.