# Math Help - chain rule in differentation.

1. ## chain rule in differentation.

Differentiate the functions using the chain rule.

$g(x) = 2(x^3 - 1 )(3x^2 +1)^4$

2. ## Re: chain rule in differentation.

Begin by using the product rule

Let $u=2(x^3 - 1)$ and $v=(3x^2 +1)^4$
You can find $\frac{du}{dx}$ easily
Use the chain rule for finding $\frac{dv}{dx}$
Let $w=3x^2 +1$ so that $v=w^4$

To find $\frac{dv}{dx}$ use the chain rule which states that $\frac{dv}{dx}=\frac{dv}{dw}\frac{dw}{dx}$

3. ## Re: chain rule in differentation.

can you give more solution ? I still can't understand.

4. ## Re: chain rule in differentation.

Originally Posted by mastermin346
can you give more solution ? I still can't understand.
Take a look at this solution.