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Thread: chain rule in differentation.

  1. March 19th 2013, 07:26 AM #1
    mastermin346
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    chain rule in differentation.

    Differentiate the functions using the chain rule.

    g(x) = 2(x^3 - 1 )(3x^2 +1)^4

    I have no idea how to use chain rule in this question..Please help !
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  2. March 19th 2013, 07:41 AM #2
    Shakarri
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    Re: chain rule in differentation.

    Begin by using the product rule

    Let u=2(x^3 - 1) and v=(3x^2 +1)^4
    You can find \frac{du}{dx} easily
    Use the chain rule for finding \frac{dv}{dx}
    Let w=3x^2 +1 so that v=w^4

    To find \frac{dv}{dx} use the chain rule which states that \frac{dv}{dx}=\frac{dv}{dw}\frac{dw}{dx}
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  3. March 19th 2013, 07:58 AM #3
    mastermin346
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    Re: chain rule in differentation.

    can you give more solution ? I still can't understand.
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  4. March 19th 2013, 08:22 AM #4
    Plato
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    Re: chain rule in differentation.

    Quote Originally Posted by mastermin346 View Post
    can you give more solution ? I still can't understand.
    Take a look at this solution.
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