What? isnt the first derivative (-xy^2+1)/(x^2*y)? i put that in the calculator and it gives me the same answer....please reply
I've done this problem two different ways and have gotten two different answers. It's very long and one simple algebraic mistake messes up everything so i was wondering if someone could find the anwer: find the second derivative of (x^2)(y^2)-2x=3. Can you use the quotient rule to find it so if i did do it wrong i can see where i made the mistake? i got (2x^2y^4-2xy^2-1)/(x^4y^3) the first time and (2x^2+y^2-2xy-1)/(x^4y^3) the second. Also, how do i find the derivative of an equation implicitly. Explicity it's d(f(x),x) but i can't figure it out implicitly. I'd rather check my work that way instead of bothering you. Thanks alot