it says
Calculate the given integral.
integral of [x^(7/2) * (ln(3x))] dx
i started it like this...
u= ln(3x) du= 1/x dx
v'= x^(7/2) v= (2/9)x^(9/2)
=ln(3x)(2/9 x^(9/2)) - 2/9[integral of x^(9/2) * (1/x) dx]
but now i'm stuck. please help
it says
Calculate the given integral.
integral of [x^(7/2) * (ln(3x))] dx
i started it like this...
u= ln(3x) du= 1/x dx
v'= x^(7/2) v= (2/9)x^(9/2)
=ln(3x)(2/9 x^(9/2)) - 2/9[integral of x^(9/2) * (1/x) dx]
but now i'm stuck. please help