
Absolute min and max
Find the absolute minimum and absolute maximum values of f on the given interval.
f(t) = 3t + 3 cot(t/2),
[π/4, 7π/4]
Hey guys, I'm stuck on this and on my last attempt, please help me out here,
so the derivative is 3/2cos(t)csc^2(t/2)
Then I make it = 0, etc,etc.
My answers I got were pi/2, 3pi/2 but they were both wrong. Please help me out here, PLEASE!

Re: Absolute min and max

Re: Absolute min and max
Ok so for pi/2 I got 3+3pi/2, for pi/4 I got 3pi/4+3cot(pi/8), 3pi/2 I got 9pi/23, and for 7pi/4 I got 21pi/43cot(pi/8)? So is the 3+3pi/2 min and 9pi/23 the max? Thanks a lot btw.

Re: Absolute min and max
Note that the absolute min and max on a closed bounded interval may be at the endpoints of the interval even if the derivative is not zero there.