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Math Help - Help understanding a Calculus 2 integral

  1. #1
    Junior Member Shadow236's Avatar
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    Question Help understanding a Calculus 2 integral

    Okay, so I've basically been practicing Calc 2 integrals non-stop because they're VERY difficult. I'm starting to get it, inch by inch, but there is one method that I just do not understand. Here is an example of my problem....



    The first step is what I don't understand. How does the 3w - 1 turn into 3 - 7/(w +2)?

    Thanks for the help.
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  2. #2
    MHF Contributor

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    Re: Help understanding a Calculus 2 integral

    It doesn't \frac{3w- 1}{w+ 2} does. Do the division: \frac{3w- 1}{w+ 2}= \frac{3w+ 6- 7}{w+ 2}= \frac{3w+ 6}{w+ 2}- \frac{7}{w+ 2}= 3\frac{w+ 2}{w+ 2}- \frac{7}{w+ 2}.
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  3. #3
    Junior Member Shadow236's Avatar
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    Re: Help understanding a Calculus 2 integral

    I can see that now. A lot of the techniques used in these integrals always seems so cryptic to me... thanks a lot!
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