It's easy, first define

Now, differentiate implicity, and yields

And we're done.

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- Oct 28th 2007, 07:47 AM #1

- Joined
- Oct 2007
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- 18

## help plz! tan^-1(s) = 1/1+s^2 how????

I have a formula that I am trying to differentiate, but having lots of problems with it:

r(s)= tan^-1 s, root of 2 /2 log(1+s^2), s - tan^-1 s)

its derivates:

r'(s) = ( ( 1+s^2)^-1, root of 2 s(1+s^2)^-1, 1- (1+s^2)-1

= (1+s^2)^-1 (1, root of 2 s, s^2)

I dont know how the derivative of tan^-1(s) = 1/1+s^2, can anyone explain?

And cannot follow how all the derivatives work out, can anyone talk me through it? I have exam shortly and ally need to get to know these off by heart.

- Oct 28th 2007, 09:37 AM #2