Results 1 to 3 of 3
Like Tree1Thanks
  • 1 Post By Prove It

Math Help - lim (t->0) (e^t-1+t)/t^2

  1. #1
    Junior Member
    Joined
    Mar 2013
    From
    Brisbane
    Posts
    33
    Thanks
    1

    lim (t->0) (e^t-1+t)/t^2

    Hi,

    I have this question:

    lim (e^t-1+t)/t^2
    t->0

    so I have used L' Hopital's Rule because when you sub in 0 you get "0/0" and arrived at

    lim e^t+1/2t
    t->0

    which i assume i would use L' Hops again if the original question was e^t-1-t/t^2 (as this derived would again give the answer "0/0") but i am not sure how to get the solution because I assume i cannot use L' Hops again because when 0 is subbed in you get "2/0". I did try this before and got the wrong answer, it says that the answer is infinity.

    Thank you very much for your time!
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor
    Prove It's Avatar
    Joined
    Aug 2008
    Posts
    11,672
    Thanks
    1497

    Re: lim (t->0) (e^t-1+t)/t^2

    Quote Originally Posted by Cotty View Post
    Hi,

    I have this question:

    lim (e^t-1+t)/t^2
    t->0

    so I have used L' Hopital's Rule because when you sub in 0 you get "0/0" and arrived at

    lim e^t+1/2t
    t->0

    which i assume i would use L' Hops again if the original question was e^t-1-t/t^2 (as this derived would again give the answer "0/0") but i am not sure how to get the solution because I assume i cannot use L' Hops again because when 0 is subbed in you get "2/0". I did try this before and got the wrong answer, it says that the answer is infinity.

    Thank you very much for your time!
    After using L'Hospital's Rule once to get to \displaystyle \lim_{t \to 0} \frac{e^t + 1}{2t} , the function is no longer of the form \displaystyle \frac{0}{0}. The top is nonzero while the bottom goes to 0, which means the limit is \displaystyle \infty .
    Thanks from Cotty
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Junior Member
    Joined
    Mar 2013
    From
    Brisbane
    Posts
    33
    Thanks
    1

    Re: lim (t->0) (e^t-1+t)/t^2

    Ahh ok thank you, I just wasn't sure whether it would have to be manipulated more but I can see it clearly now that you have pointed it out, thanks.
    Follow Math Help Forum on Facebook and Google+

Search Tags


/mathhelpforum @mathhelpforum