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Math Help - Taylor series problem AGAIN!!!!

  1. #1
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    Exclamation Taylor series problem AGAIN!!!!

    Really struggling, any help please?

    Must of been having a complete off day when the lecturer was going through taylor series, that or my insomnia... ahhh...


    Please find attached copy of the question that has baffled me!!!
    Many thanks, Hanna.
    Attached Thumbnails Attached Thumbnails Taylor series problem AGAIN!!!!-taylor-series.jpg  
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  2. #2
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    Re: Taylor series problem AGAIN!!!!

    You can use the Binomial series (which is a type of Taylor series) to help expand \displaystyle \begin{align*} \left( 1 - \frac{2}{9}x \right)^{\frac{1}{2}} \end{align*}.
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