# Taylor series problem AGAIN!!!!

• March 12th 2013, 04:36 PM
raggie29
Taylor series problem AGAIN!!!!
Really struggling, any help please?

Must of been having a complete off day when the lecturer was going through taylor series, that or my insomnia... ahhh...

Please find attached copy of the question that has baffled me!!!
Many thanks, Hanna.
• March 12th 2013, 05:22 PM
Prove It
Re: Taylor series problem AGAIN!!!!
You can use the Binomial series (which is a type of Taylor series) to help expand \displaystyle \begin{align*} \left( 1 - \frac{2}{9}x \right)^{\frac{1}{2}} \end{align*}.