# A matter regarding Leibniz notation

• Mar 11th 2013, 04:18 PM
ZeroDivisionError
A matter regarding Leibniz notation
Dear mathematicians out there,

This is just a clarification regarding an identity I encountered that I couldn't find elsewhere on the Internet. In general, is it true that
$\frac{dy/dt}{dx/dt} = \frac{dy}{dx}$
or is this just the Leibniz notation playing tricks on us?

• Mar 11th 2013, 04:28 PM
ZeroDivisionError
Re: A matter regarding Leibniz notation
Never mind. I answered my own question. You just take the chain rule
$\frac{dy}{dx} = \frac{dy}{dt} \frac{dt}{dx}$
and divide both sides by dt/dx.
$\frac{dy/dx}{dt/dx} = \frac{dy}{dt}$
Oh well, I'll be all alone here on this thread then.
• Mar 11th 2013, 04:28 PM
Prove It
Re: A matter regarding Leibniz notation
Yes, it's true. You need to remember that \displaystyle \begin{align*} \frac{1}{\frac{dY}{dX}} = \frac{dX}{dY} \end{align*}. Using this property we have

\displaystyle \begin{align*} \frac{\frac{dy}{dt}}{\frac{dx}{dt}} &= \frac{dy}{dt} \cdot \frac{1}{\frac{dx}{dt}} \\ &= \frac{dy}{dt} \cdot \frac{dt}{dx} \\ &= \frac{dy}{dx} \textrm{ by the Chain Rule} \end{align*}